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CRF = i(1+i)^n / [(1+i)^n − 1]: match history

Recent matches we tracked for this player, newest first (up to 500 per filter).

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4 games · 3–1 · 75.0% won

Match history of CRF = i(1+i)^n / [(1+i)^n − 1]
ResultCivilizationRatingOpponentsMapLengthPlayed
WinMaya
Team mates (3)
1755+3My Map21:1261 days ago
WinMalians1608+6My Map4:291 year ago
WinTatars1550+10My Map10:391 year ago
LossItalians1360-13My Map8:452 years ago